Conversion of electrical units (Capacitance) into energy and power units

Symbols used in this notes are:

F – Farad; C – Coulomb; V – Volt; A – Ampere; J –Joules; s – second; W – Watt; g – gram; h – hour

 

Correlation between electrical (capacitance) and energy and power units

F = C/V

W = A×V

C = A×s

J = W×s (Energy unit)

F =(A×s)/ V

So, F×(V^2) = A×s×V = W×s = J
Or, F = (W×s) / V^2 = J / V^2

Note:
Faraday's Constant is different from Farad. (Not confused, though both represented by symbol 'F'.)
1 Faraday = 96485 C
1 Faraday = (96485 C /3600 s) = 26.801 A·h

 

Capacitance is expressed in, F

Energy is expressed in, Wh

Power is expressed in, W

 

Specific Capacitance is expressed as: F/kg (or) F/g

Specific Energy is expressed as: Wh/kg (or) Wh/g

Specific Power is expressed as: W/kg (or) W/g

 

Assume a supercapacitor has a Specific Capacitance of 2000 F/g and discharges at a potential difference of 1 V in 900 s, then Specific Energy and Specific Power is related to its Specific Capacitance as:

 

Formula:

Specific energy = 0.5 × Specific Capacitance × (dV)^2

 

Here, Specific Capacitance = 2000 F/g and dV = 1 V

= 0.5 × 2000 F/g × (1 V)^2

= 1000 F/g V^2 = 1000 J/g

= 1000 W×s /g

= {1000 W×s /g} / 3600 = 0.2778 Wh/g       

= 0.2778 Wh/g × 1000 = 277.8 Wh/kg

So, Specific Energy = 277.8 Wh/kg

 

Specific Power = Specific Energy / time (in hour)

Discharge time = 900 s/3600 = 0.25 h

So, Specific Power = (277.8 Wh/kg) / (0.25 h) = 1111.2 W/kg

 

 

By,

Dr. M Kanagasabapathy

Associate Professor

Department of Chemistry

Rajapalayam Rajus’ College

Madurai Kamaraj University

Rajapalayam (TN) 626117 (IN)

 

 

Also check this related page:

Relations between some basic electrical units